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# Mitigating the energy landscape of a variational circuit with Mitiq

+++

This tutorial shows an example in which the energy landscape for a two-qubit variational
circuit is explored with and without error mitigation.

```{code-cell} ipython3
import matplotlib.pyplot as plt
import numpy as np
from cirq import Circuit, rx, CNOT, DensityMatrixSimulator, LineQubit, depolarize

from mitiq.zne import mitigate_executor
from mitiq.zne.inference import RichardsonFactory

SIMULATOR = DensityMatrixSimulator()
```

## Defining the ideal variational circuit
We define a function which returns a simple two-qubit variational circuit depending on a single parameter  $\gamma$.

```{code-cell} ipython3
def variational_circuit(gamma: float) -> Circuit:
    """Returns a two-qubit circuit for a given variational parameter.

    Args:
        gamma: The variational parameter.

    Returns:
        The two-qubit circuit with a fixed gamma.
    """

    q0, q1 = LineQubit.range(2)

    return Circuit([rx(gamma)(q0), CNOT(q0, q1), rx(gamma)(q1), CNOT(q0, q1), rx(gamma)(q0)])

```

We can visualize the circuit for a particular $\gamma$ as follows.

```{code-cell} ipython3
print(variational_circuit(gamma=np.pi))
```

## Defining the executor functions with and without noise
To use error mitigation methods in Mitiq, we define an executor function which computes the expectation value of a simple Hamiltonian $H=Z \otimes Z$, i.e., Pauli-$Z$ on each qubit. To compare to the noiseless result, we define both a noiseless and a noisy executor below.

```{code-cell} ipython3
# Observable to measure
z = np.diag([1, -1])
hamiltonian = np.kron(z, z)

def noiseless_executor(circ: Circuit) -> float:
    """Simulates the execution of a circuit without noise.

    Args:
        circ: The input circuit.

    Returns:
        The expectation value of the ZZ observable.
    """
    # Get the final density matrix of the circuit
    SIMULATOR = DensityMatrixSimulator()
    rho = SIMULATOR.simulate(circ).final_density_matrix
    # Evaluate the ZZ expectation value
    expectation = np.real(np.trace(rho @ hamiltonian))
    return expectation

# Strength of noise channel
p = 0.04

def executor_with_noise(circ: Circuit) -> float:
    """Simulates the execution of a circuit with depolarizing noise.

    Args:
        circ: The input circuit.

    Returns:
        The expectation value of the ZZ observable.
    """
    # Add depolarizing noise to the circuit
    noisy_circuit = circ.with_noise(depolarize(p))
    # Use the noiseless_executor function to return the expectation value of the ZZ observable for the noisy circuit
    return noiseless_executor(noisy_circuit)
```

:::{note}
The above code block uses depolarizing noise, but any Cirq channel can be substituted in.
:::

+++

## Computing the landscape without noise
We now compute the energy landscape $\langle H \rangle(\gamma) =\langle Z \otimes Z \rangle(\gamma)$ on the noiseless simulator.

```{code-cell} ipython3
gammas = np.linspace(0, 2 * np.pi, 50)
noiseless_expectations = [noiseless_executor(variational_circuit(g)) for g in gammas]
```

The following code plots the values for visualization.

```{code-cell} ipython3
plt.figure(figsize=(8, 6))
plt.plot(gammas, noiseless_expectations, color="g", linewidth=3, label="Noiseless")
plt.title("Energy landscape", fontsize=16)
plt.xlabel(r"Ansatz angle $\gamma$", fontsize=16)
plt.ylabel(r"$\langle H \rangle(\gamma)$", fontsize=16)
plt.legend(fontsize=14)
plt.ylim(-1, 1);
plt.show()
```

## Computing the unmitigated landscape
We now compute the unmitigated energy landscape $\langle H \rangle(\gamma) =\langle Z \otimes Z \rangle(\gamma)$
in the following code block.

```{code-cell} ipython3
gammas = np.linspace(0, 2 * np.pi, 50)
expectations = [executor_with_noise(variational_circuit(g)) for g in gammas]
```

The following code plots these values for visualization along with the noiseless landscape.

```{code-cell} ipython3
plt.figure(figsize=(8, 6))
plt.plot(gammas, noiseless_expectations, color="g", linewidth=3, label="Noiseless")
plt.scatter(gammas, expectations, color="r", label="Unmitigated")
plt.title(rf"Energy landscape", fontsize=16)
plt.xlabel(r"Ansatz angle $\gamma$", fontsize=16)
plt.ylabel(r"$\langle H \rangle(\gamma)$", fontsize=16)
plt.legend(fontsize=14)
plt.ylim(-1, 1);
plt.show()
```

## Computing the mitigated landscape
We now repeat the same task but use Mitiq to mitigate errors.
We initialize a RichardsonFactory with scale factors `[1, 3, 5]` and we get a mitigated executor as follows.

```{code-cell} ipython3
fac = RichardsonFactory(scale_factors=[1, 3, 5])
mitigated_executor = mitigate_executor(executor_with_noise, factory=fac)
```

We then run the same code above to compute the energy landscape, but this time use the ``mitigated_executor`` instead of just the executor.

```{code-cell} ipython3
mitigated_expectations = [mitigated_executor(variational_circuit(g)) for g in gammas]
```

Let us visualize the mitigated landscape alongside the unmitigated and noiseless landscapes.

```{code-cell} ipython3
plt.figure(figsize=(8, 6))
plt.plot(gammas, noiseless_expectations, color="g", linewidth=3, label="Noiseless")
plt.scatter(gammas, expectations, color="r", label="Unmitigated")
plt.scatter(gammas, mitigated_expectations, color="b", label="Mitigated")
plt.title(rf"Energy landscape", fontsize=16)
plt.xlabel(r"Variational angle $\gamma$", fontsize=16)
plt.ylabel(r"$\langle H \rangle(\gamma)$", fontsize=16)
plt.legend(fontsize=14)
plt.ylim(-1.5, 1.5);
plt.show()
```

Noise usually tends to flatten expectation values towards a constant. Therefore error mitigation
can be used to increase the visibility the landscape and this fact can simplify the energy minimization
which is required in most variational algorithms such as VQE or QAOA.

We also observe that the minimum of mitigated energy approximates well the theoretical ground state which is equal to $-1$. Indeed:

```{code-cell} ipython3
print(f"Minimum of the noisy landscape: {round(min(expectations), 3)}")
print(f"Minimum of the mitigated landscape: {round(min(mitigated_expectations), 3)}")
print(f"Theoretical ground state energy: {min(np.linalg.eigvals(hamiltonian))}")
```